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A sinusoidal voltage of peak value `283 V` and frequency `50 Hz` is applied to a series `LCR` circuit in which `R = 3 Omega, L = 25.48 mH`, and `C = 796 mu F`. Find the impdedance of the circuit. |
Answer» Correct Answer - 5 To find the impedance of the circuit, we first calculate `X_(L)` and `X_(C)`. `X_(L)=2pifL` `=2xx3.14xx50xx25.48xx10^(-3)Omega=8Omega` `X_(C)=(1)/(2pifC)=(1)/(2xx3.14xx50xx796xx10^(-6))=4Omega` Therefore, `Z=sqrt(R^(2)+(X_(L)-X_(C))^(2))=sqrt(3^(2)+(8-4)^(2))=5Omega` |
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