Saved Bookmarks
| 1. |
A sinusoidal voltage of peak value of 283 V and frequency 50 Hz is applied to a series LCR circuit in which R = 3 Omega , L = 25.48 mH and C = 796 mu F. Find the impedance of the circuit. |
|
Answer» Solution :(i) `X_(L) = omega L` `= 2 pi f L` `= ( 2) ( 3.14) ( 50) ( 25.48 xx 10^(-3))` `= 8 Omega` (ii) `X_(C ) = ( 1)/( omega C )` `= ( 1)/( 2pi f C )` `= ( 1)/( 2 xx 3.14 xx 50 xx 796 xx 10^(-6))` `= 4.00 1 Omega` `= 4 Omega` (iii) Impedance of given SERIES ac circuit. `|Z | = SQRT ( R^(2) + ( X_(L) - X_(C ))^(2))` `= sqrt( (3)^(2) + ( 8-4)^(2)) = 5 Omega` |
|