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A sinusoidal voltage of peak value of 283 V and frequency 50 Hz is applied to a series LCR circuit in which R = 3 Omega , L = 25.48 mH and C = 796 mu F. Find the power dissipated in the circuit, and |
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Answer» Solution :POWER dissipated in the FORM of heat is , `P= I_(rms) ^(2) R` `= { ( V_(rms))/( |Z|)}^(2) R` `= { ( V_(m))/( sqrt(2)|Z|)}^(2) R` `( :. V_(rms) = ( V_(m))/(sqrt(2)) )` `= ( V_(m) ^(2)R)/( 2 | Z|^(2)) = (( 283)^(2) ( 3))/((2) (5)^(2)) ` `:. P = 4805 W ` ( WATT ) OR `I= I_(rms) = ( V_(rms))/( Z ) = ( V_(m))/( sqrt( 2) Z)= ( 283)/( 1.414 xx 5 )` `P = I^(2) R = ( 40.028)^(2) xx 4800 W ` |
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