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A sinusoidal voltage `V (t) = 100 sin (500 t)` is applied across a pure inductance of `L = 0.02 H`. The current through the coil is :A. `10 cos (500 t)`B. `- 10 cos (500 t)`C. `10 sin (500 t)`D. `- 10 sin (500 t)` |
Answer» Correct Answer - 2 `i = i_(0) sin (omega t - (pi)/(2)), i_(0) = (V_(0))/(X_(L))` |
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