1.

A sinusoidal voltage V(t) = 100 sin (500t)is applied across a pure inductance of L = 0.02 H. the current through the coil is

Answer»

10 cos (500t).
`-10` cos (500t).
10 sin (500t)
`-10` sin (500t)

Solution :(b) Voltage across pure inductor
`V_(L)(t) = L (di)/(dt)`
`int_(0)^(i) dt = int_(0)^(t) (V(t))/(L) dt`
`I = int_(0)^(t) (1000sin(500t))/(0.02)dt `
`= (-100xx100)/(2)XX((cos(500t))/(500))`
`i=-10cos (500t) +C`
Here C is ZERO .


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