1.

A slab of a material of dielectric constaant 2 is placed between two identical parallel plates. One of the plates carries total charge density +2mC/m^(2) and the other plate carries total charge density -4mC/m^(2) the magnitude of electric field inside the dielectric in (in 10^(11)N//C) Take epsi_(0)=(80)/(9)xx10^(-12)Nm^(2)//C^(2))

Answer»

2.25
3.38
4.5
6.75

Solution :The inner surfaces of the TWO plates will CARRY CHARGE density `+3mC//m^(2) and -3mC//m^(2)` respectively. THEREFORE, field between the plates,
`E=(sigma)/(epsi_(0))=(3)/((80)/(9)xx10^(-12))=3.38xx10^(11)N//C`


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