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A slab of material of dielectric constant K has the same area as that of the plates of a parallel plate capacitor but has the thickness d/2, where d is the separation between the plates. Find out the expression for its capacitance when the slab is inserted between the plates of the capacitor. |
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Answer» Solution :We KNOW that capacitance of a parallel PLATE capacitor is given as `C = (epsi_0A)/d` where A is AREA of eachplate and d is the DISTANCE between them. If a dielectric SLAB of dielectric constant K and area A but of thickness t (t In present case t = d/2. Hence capacitance of the capacitor will be `C = (epsi_0A)/(d - d/2((K-1)/K))=(2 epsi_0A)/(2d-d((K-1)/K)) =(2epsi_0A)/(d(1 +1/K))` |
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