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A slit of width d is placedin front of a lens of focal length 0.5 m and is illuminated normally with light of wavelength 5.89 xx 10^(-7)m. The first diffraction minima on either side of the central max. Are separated by 2 xx 10^(-3)m. The width of the slit is : |
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Answer» `1.47 xx 10^(-4)` m `2theta = (2lambda)/(d)` LINEAR width `2y = 2((lambda)/(d))f`" `[because (lambda)/(d) = theta]` `therefore d = (2lambda.f)/(2y) = 2.92 xx 10^(-4)m`. |
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