1.

A slope of a graph In [A] versus 't' for a first order is -5 xx 10^(-4)s^(-1). The rate constant for the reaction will be.

Answer»

`10 xx 10^(-3)s^(-1)`
`2.5 xx 10^(-3) s^(-1)`
`1.086 xx 10^(-3) s^(-1)`
`5 xx 10^(-3) s^(-1)`

SOLUTION :For 1ST ORDER
In `[A] = - kt + In [A]_0` hence SLOPE = - k
`:. K = -"slope"`
`=-(-5 xx 10^(-3))s^(-1)`
` =+5 xx 10^(-3)s^(-1)`


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