InterviewSolution
Saved Bookmarks
| 1. |
A small bar magnet has a magnetic moment `1.2 A-m^(2)`. The magnetic field at a distance `0.1 m` on its axis will be: `(mu_(0)=4pixx10^(-7)T-m//A)`A. `1.2xx10^(-4)T`B. `2.4xx10^(-4)T`C. `2.4xx10^(4)T`D. `1.2xx10^(4)T` |
|
Answer» Correct Answer - B `B=mu_(0)/(4pi).(2M)/d^(3) implies B=10^(-7)xx(2xx1.2)/(0.1)^(3)=2.4xx10^(-4)T` |
|