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A small block of mass `1` kg is a circular are of ratius `40` m . The block sides along the track without topping and a frictionnal force acts on it in the direction opposite in the instrmens velocity . The work done in evercoming the friction up to the point `Q` as shown is the figure below is `150 J` (Take the acceleration due to gravity `g = 10 ms^(-2))` The magnitude of the normal reaction that acts on the block at the point `Q` isA. (a) `7.5N`B. (b) `8.6N`C. (c) `11.5N`D. (d) `22.5N` |
Answer» Correct Answer - A `N-mg cos 60^@=(mv^2)/(R)` `N=5+5/2=7.5N c` |
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