1.

A small block slides without friction down an inclined plane starting from rest. Lets s_n be the distance travelled from time t=n - 1 to t = n. Then (S_n)/(s_n+1) is:

Answer»

`(2N-1)/(2n)`
`(2n+1)/(2n-1)`
`(2n-1)/(2n+1)`
`(2n)/(2n+1)`

SOLUTION :Here ` S_(N)=u+a//2(2n-1)`
As u=0
`:. S_(n)=a//2(2n-1)`
ALSO `S_(n+1)=a//2 [2n(n+1)-1]=a//2[2n+1]`
HENCE `(S_(n))/(S_(n+1))=(2n-1)/(2n+1)`


Discussion

No Comment Found

Related InterviewSolutions