InterviewSolution
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InterviewSolution
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A small bob attached to a light inextensible thread of length `l` has a periodic time `T` when allowed to vibrate as a simple pendulum. The thread is now suspended from a fixed end `O` of a vertical rigid rod of length `3l//4`. If now the pendulum performs periodic oscillations in this arrangement, the periodic time will be A. `3T//4`B. `4T//5`C. `2T//3`D. `5T//6` |
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Answer» Correct Answer - A Half of the oscillation is completed with length `l` and rest half with `l//4`. `:.` Time period `= (T_(1))/(2) + (T_(2))/(2)` `= (1)/(2)[2pi sqrt((l)/(g)) + 2pi sqrt((l//4)/(g))]` `= (3)/(4)[2pi sqrt((l)/(g))] = (3)/(4)T` |
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