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A small bulb is placed at the bottom of a tank containing water to a depth of 1m. Find the criticalangle for water air interface ,also calculate the diameter of the circular bright patch of light formed on the surface of water.[ R.I of water =4/3] |
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Answer» SOLUTION :Given : `n=4//3` , C=? , d=1m , `n=1//sinC` `sin C=1//n rArr sin C=1/(4//3)=3/4 rArr C = sin^(-1) (3//4)` `C=48.6^@` W.K.T. `r/h`=tan C tan C x h =r tan `48.6^@` x 1 m =2 r=1.1343 x 1 r=1.1343 d=2r=2 x 1.1343 d=2.2686 m 
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