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A small electric dipole having dipole moment vec p is placed along x-axis as shown in the figure . A semi-infinite uniformly charged di-electric thin rod is placed along x axis , with one end coinciding with origin . If linear charge density of rod is + lambda and distance of dipole from rod is a then calculate the electric force acting on dipole . |
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Answer» `dE = (K lambdadx)/(x^2)` `E = int dE = K LAMBDA int _a^(infty) = (K lambda)/a = 1/(4 pi in_0) (lqambda)/a` ` (##NG_PHY_C01_E01_113_S01.png" width="80%"> POTENTIAL energy of dipole `U =- Pe COS theta` `U = - ( p lambda) /( 4 pi in_0 a)` `F= - (dU)/(da) rArr F= ( lambda )/(4pi in_0 a^2)`. |
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