A small, electrically charged bead can slide on a circular, frictioless, insulating rod. A point - like electric dipole (vec(P)) is fixed at the centre of the circle with the dipole.s axis lying in the plane of the circle. Intially the bead is on the plane of symmetry of the dipole, as shown in the figure. The bead is slightly displaced along ring, tangentially with intial speed very close to zero. (Ignore the effect of gravity, assuming that the electric forces are much greater than the gravitational ones). How would the bead move in the absence of rod (intial motion is perpendicular to and negligibly small)

A small, electrically charged bead can slide on a circular, frictioles

1.	A small, electrically charged bead can slide on a circular, frictioless, insulating rod. A point - like electric dipole (vec(P)) is fixed at the centre of the circle with the dipole.s axis lying in the plane of the circle. Intially the bead is on the plane of symmetry of the dipole, as shown in the figure. The bead is slightly displaced along ring, tangentially with intial speed very close to zero. (Ignore the effect of gravity, assuming that the electric forces are much greater than the gravitational ones). How would the bead move in the absence of rod (intial motion is perpendicular to and negligibly small)
Answer» On circular PATH, as it was moving with the frictionless, circular, INSULATING rod radially TOWARDS dipole tangential intially, but AFTERWARD it can not be predicted Answer :A

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