A small, electrically charged bead can slide on a circular, frictioless, insulating rod. A point - like electric dipole (vec(P)) is fixed at the centre of the circle with the dipole.s axis lying in the plane of the circle. Intially the bead is on the plane of symmetry of the dipole, as shown in the figure. The bead is slightly displaced along ring, tangentially with intial speed very close to zero. (Ignore the effect of gravity, assuming that the electric forces are much greater than the gravitational ones). The normal force exerted by rod on the bead is (q = angle between an radius vector of bead, (considering dipole as origin)

A small, electrically charged bead can slide on a circular, frictioles

1.	A small, electrically charged bead can slide on a circular, frictioless, insulating rod. A point - like electric dipole (vec(P)) is fixed at the centre of the circle with the dipole.s axis lying in the plane of the circle. Intially the bead is on the plane of symmetry of the dipole, as shown in the figure. The bead is slightly displaced along ring, tangentially with intial speed very close to zero. (Ignore the effect of gravity, assuming that the electric forces are much greater than the gravitational ones). The normal force exerted by rod on the bead is (q = angle between an radius vector of bead, (considering dipole as origin)
Answer» <P>`(2K\|vec(p)\|theta.costheta)/(r^(3))` `(K\|vec(p)\|theta.costheta)/(r^(3))` ZERO `(K\|vec(p)\|theta.sintheta)/(r^(3))` Answer :C

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