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A small mass attached to a string rotates on a frictionless table top as shown in Fig. If the tension in the string is increased by pulling the string causing the radius of the circular motion to decrease by a factor of 2, the kinetic energy of the mass will A. `(1)/(4)mv_(0)^(2)`B. `2mv_(0)^(2)`C. `(1)/(2)mv_(0)^(2)`D. `mv_(0)^(2)` |
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Answer» Correct Answer - B Angular momentum remains constant because the torque of tension is zero. `:. L_(i) = L_(f) or mv_(0) R = mv (R )/(2) or v = 2v_(0)` `:.` final kinetic energy `K_(f) = (1)/(2)m (2v_(0))^(2)` `= 2mv_(0)^(2)` |
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