Saved Bookmarks
| 1. |
A small object stuck on the surface of a glass sphere (mu = 1.5) is viewed from the diametrically opposite position. Find transverse magnification |
|
Answer» Solution :Refraction will take place at side II of the surface `(mu_2)/(v )- (mu _1)/(u ) = (mu_2 -mu_1)/( R)`  Here `mu_1, = 1.5, mu_2 , = 1 and u=-2R ` `(1)/(v ) - (1.5)/((-2R)) =(1-1.5 )/(-R)` ` (1)/(v)= (0.5 )/(R )-(1.5)/( 2R ) = (-0.5 )/(2R) or v=-4R ` Negative sign INDICATES that the image is formed to the LEFT of refracting surface as shown. Magnification ` m= (mu_1 v)/(mu_2 u )=(1.5 (-4R))/( 1(-2R))` ` therefore m=3` |
|