A small particle of mass `036g` rests on a horizontal turntable at a distance `25cm` from the axis of spindle. The turntable is acceleration at rate of `alpha=(1)/(3)rads^(-2)` . The frictional force that the table exerts on the particle `2s` after the startup isA. `40muN`B. `30muN`C. `50muN`D. `60muN`

A small particle of mass `036g` rests on a horizontal turntable at a d

1.	A small particle of mass `036g` rests on a horizontal turntable at a distance `25cm` from the axis of spindle. The turntable is acceleration at rate of `alpha=(1)/(3)rads^(-2)` . The frictional force that the table exerts on the particle `2s` after the startup isA. `40muN`B. `30muN`C. `50muN`D. `60muN`
Answer» Correct Answer - C `f=ma=msqrt(a_(t)^(2)+a_(r)^(2))` `=msqrt((Ralpha)^(2)+(Romega)^(2))` `=msqrt((Ralpha)^(2)+[R(alphat)^(2)]^(2))` `=0.36xx10^(-3)sqrt((0.25xx(1)/(3))^(2)+[0.25((1)/(3)xx2)^(2)]^(2)` `=50xx10^(-6)N` `=50muN`

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