1.

A small particle of mass `m` attached with a light inextensible thread of length `L` is moving in a verical circle. In the given case particle is moving in complete vertical circle and ratio of its maximum to minimum velocity is `2:1` . Minimum velocity of the particle is A. `4sqrt((gL)/(3))`B. `2sqrt((gL)/(3))`C. `sqrt((gL)/(3))`D. `3sqrt((gL)/(3))`

Answer» Correct Answer - B
Maximum velocity is at bottommost point and minimum velocity is at tomost point.
`sqrt(u_(min)^(2)+2g(2L))/(u_(min))=(2)/(1)`
On solving, we get
`u_(min)=2sqrt((gL)/(3))`


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