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A small particle of mass `m` attached with a light inextensible thread of length `L` is moving in a verical circle. In the given case particle is moving in complete vertical circle and ratio of its maximum to minimum velocity is `2:1` . Kinetic energy of the particle at the lower most position is A. `(4mgL)/(3)`B. `2mgL`C. `(8mgL)/(3)`D. `(2mgL)/(3)` |
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Answer» Correct Answer - C `u_(max)=2u_(min)=4sqrt((gL)/(3))` :. `K_(max)=(1)/(2)mu_(max)^(2)=(8mgL)/(3)` |
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