1.

A small photocell is placed at a distance of 4 m from a photosensitive surface. When light falls on the surface the current is 5 mA. If the distance of cell is decreased to 1 m, the current will become

Answer»

`1.25 mA`
`(5/16) mA`
20 mA
80 mA

Solution :`I PROP (1)/(d^2)`


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