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A small pin fixed on a table top is viewed from above from a distance of 50 cm. By what distance would the pin appear to be raised if it is viewed from the same point through a 15 cm thick glass slab held parallel to the table ? Refractive index of glass = 1.5. Does the answer depend on the location of the slab ? |
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Answer» Solution :Here real thickness of glass slab h = 15 cm, refractive index of glass n = 1.5. If the pin APPEARS to be RAISED by X cm, then apparent thickness h. = (15 - x) cm `therefore 1.5 = h/(h^(.)) = 15/(15-x) rArr x= 5 cm` The answer does not DEPEND on the location of the glass slab. |
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