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InterviewSolution
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A small satellite revolves around a heavy planet in a circular orbit. At a point in its orbit an impulse acts suddenly and instantaneously increases its kinetic energy `K` times without change in its direction of motion. The ratio of maximum to the minimum distance from the planet is [Assume mass of satellite is negligible small compared to that of planet]A. `K/(K+2)`B. `K/(K-2)`C. `(K+2)/K`D. `(2-K)/K` |
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Answer» Correct Answer - B `-int_(P_(c))^(0)dp=4/3Grho_(r)^(2)int_(0)^(R)rdr` ltBrgt `P_(c)=4/3piGrho_(r)^(2)(R^(2))/2` `P_(c)=(GM_(0)^(2))/(R_(0)^(4))xx(3/(2pi))` |
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