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InterviewSolution
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A small stone, of mass 200 g, is tied to one end of string of length 80 cm. Holding the other end in hand, the stone is whirled into a vertical circle. What is the minimum speed, that needs to be imparted, at the lowest point of the circular path, so that the stone is just able to complete the vertical circle? What would be the tension in the string at the lowest point of circular path? (Take g = 10 ms-2) |
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Answer» We know that vmin = minimum speed needed at the lowest point, so that particle is just able to complete vertical circle = \(\sqrt{5gl}\) Hence vmin = \(\sqrt{5\times 10\times 0.8}\) ms-1 = 6.32 ms-1 Also T1 = Tension in the string at the lowest point of its circular path = \(\frac{mv^2_1}{l}+mg\) = 6 mg = 6 × 0.2 × 10 N = 12 N |
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