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A small telescope has an objective lens of focal length 144 cm and eyepiece of focal length 6.0 cm. What is the magnifying power of the telescope ? What is the separation between the objective and the eyepiece?

Answer»

Solution :`f_(0) = 144 cm, f_(E) = 6 cm "" THEREFORE m = (f_(0))/(f_(e)) = (144)/(6) = 24 `
`L = f_(0) + f_(e) = 144 + 6 = 150 cm `


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