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A small telescope has an objective lens of focal length 140 cm and an eyepiece of focal length 5.0 cm. What is the magnifying power of the telescope for viewing distant objects whena) the telescope is in normal adjustment (i.e., when the final image is at infinity) ? |
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Answer» Solution :Here, `f_(0)=140cm, f_(E)=5.0cm` Magnifying power = ? a) In NORMAL adjustment, Magnifying power `=(f_(0))/(-f_(e))=(140)/(-5)=-28` |
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