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A small telescope has an objective lens of focal length `144 cm` and an eye-piece of focal length `6.0 cm`. What is the magnifying power of the telescope ? What is the separation between the objective and the eye-piece ?

Answer» Here, `f_(0) = 144 "cm" , f_(e) = 6.0"cm" , MP = ? L =?`
`MP = (-f_(0))/(f_(e)) = (-144)/(6.0) = -24 "and" L = f_(0) + f_(e) = 144 + 6.0 = 150.0 "cm"`


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