1.

A smooth hoop lie as on a smooth horizontal table and is fixed. A particle is projected on the table form a point A on the inner circumference of the hoop at angle theta with radius vector . If e be the coefficient of restitution and the particle returns to the point of projection after two successive impacts. The final angle theta' made by velocity vector with radius of hoop is

Answer»

`tan theta' = ( e^(2))/( ( 1+ e^(2))) tan theta `
`tan theta' = e^(2) tan theta `
`tan theta ' = ( tan theta )/( e^(2))`
`tan theta' = ( tan theta)/( e )`

Answer :C


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