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A smooth square platform ABCD is moving towards right with a uniform speed v. At what angle `theta` must a particle be projected from A with speed u so that it strikes the point B A. `sin^(-1)(u/v)`B. `cos^(-1)(v/u)`C. `cos^(-1)(u/v)`D. `sin^(-1)(v/u)` |
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Answer» Correct Answer - b Particle will strike the point B if velocity of particle with respect to platform is along AB or component of its relative along AD is zero. So, `u cos theta=v` or `theta=cos^(-1)(v/u)` |
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