1.

A soap bubble 'A' of radius 0.03 m and another bubble 'B' of radius 0.04 m are brought together so that the combined bubble has a common interface of radius r, then the value of r is :

Answer»

<P>0.06 m
0.012 m
0.12 m
0.035 m

Solution :Here `P_(a)=(4T)/(0.03),P_(b)=(4T)/(0.05)` As `P_(a)gtP_(b)`, the INTERFACE between A and B is CONVEX.
`(4T)/(0.03)-(4T)/(0.04)=(4T)/r` or r=0.12 m
`therefore` CORRECT choice is (c).


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