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A soap bubble 'A' of radius 0.03 m and another bubble 'B' of radius 0.04 m are brought together so that the combined bubble has a common interface of radius r, then the value of r is : |
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Answer» <P>0.06 m `(4T)/(0.03)-(4T)/(0.04)=(4T)/r` or r=0.12 m `therefore` CORRECT choice is (c). |
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