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A soap film measure `10cmxx6cm`. It is increased to `10cmxx12cm`. IF surface tension is `30xx10^-3` newtor per metre. Then the work done isA. `3.6xx10^0J`B. `3.6xx10^-2J`C. `3.6xx10^-4J`D. `3.6xx10^3J` |
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Answer» Correct Answer - C `W=2[120xx10^-4-60xx10^-4]30xx10^-3J` `=2xx60xx10^-4xx30xx10^-3J=3.6xx10^-4J` |
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