Saved Bookmarks
| 1. |
A soild sphere is initially kept in open air, and the pressure exerted on it by air is 1.0xx10^(5)N//m^(2) (atmospheric pressure). The sphere is lowered into the ocean to a depth where the pressure is 200 times the atmospheric pressure. The volume of the sphere in air is 0.5 m^(3). What is the change in the volume once the sphere is submerged ? Given that bulk modulus is 6.1xx10^(10)N//m^(2). |
|
Answer» Solution :What happens when you squeeze a tennis ball in your hand ? Its volume REDUCES as it shrinks. We can expect same to happen to the sphere when it is subjected to high pressure from the ocean water. We need to perform a SIMPLE calculation using Eq. 12-5. `Delta U=-(V,Delta p)/(B)`. Substituting the numerical VALUES : `Delta V=((0.50 m^(3))(2.0xx10^(7)N//m^(2)-1.0xx10^(5)N//m^(2)))/(6.1xx10^(10)N//m^(2))` `=-1.6xx10^(-4)//m^(3)`. The NEGATIVE sign indicates that the volume of the sphere decreases when submerged. |
|