A solenoid has core of a material with relative permeability 200 and its windings carry a current of 2 A. The number of turns of the solenoid is 200 per meter. What is the magnetization of the material?(a) 6 × 10^4 A/m(b) 7 × 10^4 A/m(c) 8 × 10^4 A/m(d) 9 × 10^4 A/mThe question was posed to me in an interview for internship.This interesting question is from Solenoid and Toroid in chapter Moving Charges and Magnetism of Physics – Class 12

A solenoid has core of a material with relative permeability 200 and i

1.	A solenoid has core of a material with relative permeability 200 and its windings carry a current of 2 A. The number of turns of the solenoid is 200 per meter. What is the magnetization of the material?(a) 6 × 10^4 A/m(b) 7 × 10^4 A/m(c) 8 × 10^4 A/m(d) 9 × 10^4 A/mThe question was posed to me in an interview for internship.This interesting question is from Solenoid and Toroid in chapter Moving Charges and Magnetism of Physics – Class 12
Answer» The correct answer is (c) 8 × 10^4 A/m The explanation: Given: number of TURNS (n) = 200 turns per meter; CURRENT (I) = 2 A; RELATIVE permeability (µr) = 200 Magnetic INTENSITY is given by: H = nI = 200 × 2 = 400 A/m μr = 1 + γ → γ is the magnetic susceptibility of the material γ = μr – 1 Magnetization → M = γ x H M = (μr – 1) × H M = (200 – 1) × 200 M = 199 × 200 M = 79600 M = 7.96 × 10^4A/m ≈ 8 × 10^4 A/m

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