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A solenoid having 2000 turns/m has a core of a material with relative permeability 220. The area of core is `4cm^(2)` and carries a current of 5A. Calculate (a) Magnetic intensity (b) Magneic field (c ) Magnetisation (I) of the core Also calculate the pole strength developed. |
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Answer» Given `n=2000 turns,I=5A, mu_(r)=220,A=4cm^(2)` (a) Magnetic intensity, `H=nI=2000xx5=1000A//m` (b) Magnetic field, `B=muH=mu_(0)mu_(r)h` `" " 4pixx10^(-7)xx220xx10000=88pixx10^(-2)T` (C ) As we know , `B=B_(0)(H+I)` `" "88pixx10^(-2)=10^(4)+I` `Rightarrow 2.20xx10^(6)=10^(4)+I` `" " I=(2.20xx10^(6)-10^(4))=2.19xx10^(6)A//m` (d) Pole strength, m=`(2.19xx10^(6))(4xx10^(-4))=876A//m` |
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