InterviewSolution
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InterviewSolution
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A solenoid having 5000 turns/m carries a current of 2A. An aluminium ring at temperature 300K inside the solenoid provides the core, (a) If the magnetisation I is `2xx10^(-2)A/m`. Find the susceptibility of aluminium at 300K (b) If temperature of the aluminium ring is 320K, what will be the magnetisation ? |
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Answer» `H=I=5000xx2=10^(4)A//m` `" " I=chiH` `" " chi=(I)/(H)=(2xx10^(2))/(10^(4))=2xx10^(-6)` (b) According to Curie law `" " chi=(C)/(T) Rightarrow (chi_(2))/(chi_(1))=(T_(2))/(T_(1))` `" " chi_(2)=(T_(2))/(T_(1))chi_(1)=(320)/(300)xx2xx10^(-6)=2.13xx10^(-6)` Manetisation at 320K `I=chi_(2)H=2.13xx10^(-6)xx10^(4)=2.13xx10^(-2)A//m` |
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