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A solenoid is of length 20 cm and consists of 1000 turns. When a current of 2A is passed through the coil of the solenoid, what is the value of magnetic induction at the centre of the solenoid. DATA: i=5A, N=1000 l=20 cm =0.2 m mu_@=4pixx10^(-7) ((Wb)//A To find:B=? |
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Answer» Solution :Magnetic FIELD B at the CENTRE of the SOLENOID: `B=mu_@xx(N/l)xxi` `(4xx3.14xx10^(-7)xx1000xx2)/(0.2)`=0.1256T. |
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