A solenoid of cross-sectional area `2xx 10^(-4)m^(2)` and 900 turns has `0.6A m^(2)` magnetic moment. Then the current flowing through it isA. 2.4AB. 2.34mAC. 3.33AD. 3.33mA

A solenoid of cross-sectional area `2xx 10^(-4)m^(2)` and 900 turns ha

1.	A solenoid of cross-sectional area `2xx 10^(-4)m^(2)` and 900 turns has `0.6A m^(2)` magnetic moment. Then the current flowing through it isA. 2.4AB. 2.34mAC. 3.33AD. 3.33mA
Answer» Correct Answer - C Here, N=900 turns `A=2xx10^(-4)m^(2), m_(s)=0.6Am^(2)` The magnetic moment of solenoid `m_(s)=NIA` The current flowing through the solenoid is `I=(m_(s))/(NA)=(0.6)/(900xx2xx10^(-4)=3.33A`

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A solenoid of cross-sectional area `2xx 10^(-4)m^(2)` and 900 turns has `0.6A m^(2)` magnetic moment. Then the current flowing through it isA. 2.4AB. 2.34mAC. 3.33AD. 3.33mA

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