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A solenoid of length 0.5 m has a radius of 1 cm and is made up of 500 turns. It carries a current of 5 A. What is the magnitude of magnetic fieldinside the solenoid ? |
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Answer» SOLUTION :The NUMBER of turns per UNIT LENGHT is , `n = (500)/(0.5)` = 1000 tuns / m The leght l =0.5 m and radius r=0.01 m . Thus `l/a`= 50, i,e ` l gt gt a.` Hence , we can use the long solenoid formula `B=mu_(0) n l = 4 pixx 10^(-7) xx 10^(3) xx 5= 6. 28xx 10^(-3) T` |
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