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A solenoid of length 22.5 cm has a total of 900 turns and carries a current of 0.8 A. What is the magnetising field H near the centre and far away from the ends of the solenoid ? |
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Answer» `l = 22.5 cm = 22.5 xx 10^(-2) m = (45)/(2) xx 10^(-2)m` `N = 900, I = 0.8A, H = ?` `H = (NI)/(l) = (900 xx 0.8)/((45)/(2)xx10^(-2))` `H = (900)/(45) xx 0.8 xx 10^(2) xx 2` `:. H = 3200 Am^(-1)`. |
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