1.

A solenoid of length 3.14 cm has a radius of 1 cm and is made up of 500 turns. It carries a current of 5 A. What is the magnitude of the magnetic field inside the solenoid ?

Answer»

Solution :For a current carrying long SOLENOID, magnitude of magnetic field produced inside the solenoid PARALLEL to its axis is,
`B=mu_(0)NI`
`=mu_(0)(N/l)I`
`=(4pixx10^(-7))(500/0.5)(5)`
`=20xx3.14xx10^(-4)`
`thereforeB=6.28xx10^(-3)T`


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