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A solenoid of length 3.14 cm has a radius of 1 cm and is made up of 500 turns. It carries a current of 5 A. What is the magnitude of the magnetic field inside the solenoid ? |
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Answer» Solution :For a current carrying long SOLENOID, magnitude of magnetic field produced inside the solenoid PARALLEL to its axis is, `B=mu_(0)NI` `=mu_(0)(N/l)I` `=(4pixx10^(-7))(500/0.5)(5)` `=20xx3.14xx10^(-4)` `thereforeB=6.28xx10^(-3)T` |
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