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                                    A solenoid of length 50cm with 20 turns per centimetre and area of cross-section 40cm^2completely surrounds another coaxial solenoid of the same length, area of cross-section 25cm^2with 25 turns per centimetre. Calculate the mutual inductance of the system. | 
                            
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Answer» Solution :`L= 50 CM = 1/2 m`  `N_1 = 20 XX 50 = 1000, A_1 = 40 xx 10^(-4) m^2` `N_2 = 25 xx 50 = 1250 , A_2 = 25 xx 10^(-4) m^2` `M = (mu_0 N_1N_2A_2)/(l)` ` = (4pi xx 10^(-7) xx 1000 xx 1250 xx 25 xx 10^(-4) )/(1//2) H` ` = 7.9 xx 10^(-3) H = 7.9 mH`  | 
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