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A solenoid of length 50cm with 20turns per centimetre and area of cross-section 40cm^(2) completely surrounds another co-axisal solenoid of the same length, area of cross-section 25cm^(2) with 25 turns per centimetre. Calculate the mutual inductance of the system. |
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Answer» Solution :`l= 50cm = (1)/(2)m` `N_(1)= 20 xx 50 = 1000, A_(1)= 40 xx 10^(-4) m^(2)` `N_(2)= 25 xx 50 = 1250, A_(2)= 25 xx 10^(-4) m^(2)` `M= (mu_(0)N_(1)N_(2)A_(2))/(1)` `=(4pi xx 10^(-7) xx 1000 xx 1250 xx 25 xx 10^(-4))/(1//2)H` `=7.9 xx 10^(-3) H= 7.9mH` For CALCULATION of M, we have to consider the cross-sectional area of the inner solenoid. |
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