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A solenoid of length l metre has self inductance L henry. If number of turns are doubled, its self inductance

Answer»

Becomes 2 L HENRY
Becomes 4 L henry
Remains same
Becomes `(L)/(sqrt(2))` henry

Solution :For a solenoid, SELF inductance `L=(mu_(0)N^(2)A)/(l)`
`(L)/(L.)=((N)/(N.))^(2)=((N)/(2N))^(2)=(1)/(4)RARR L.=4 L`henry


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