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A solenoid S_1 is placed coaxially inside another solenoid S_2 . The radii of the inner and outer solenoids are r_1 and r_2respectively. If N_1 and N_2are the number of turns of coil in solenoid S_1 and S_2respectively and l is the length of solenoid S_2 carrying current I , then calculate the mutual inductance between the two solenoids. |
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Answer» Solution : Magnetic field of the OUTER solenoid is `B = (mu_0 N_2I)/(l)` , whencurrent I PASSES through it The flux associated with the inner coil is`phi_1 = N_1 B pi r_1^2` `rArr phi_1 = N_1 ((mu_0 N_2)/(l)) I pi r_1^2` `therefore` Mutual inductance between the TWO solenoid is GIVEN by `M = (phi_1)/(I) = ((mu_0 N_1N_2)/(l)) pi r_1^2` |
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