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A solenoidal coil has 50 turns per centimetre along its length and a cross-sectional area of 4 xx 10^(-4) m^(2). 200 turns of another wire is wound round the first solenoid co-axially. The two coils are electrically insulated from each other. Calculate the mutual inductance between the two coils. |
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Answer» Solution :`n_(1)= 50` turns per CM =5000 turns per metre `n_(2)L= 200, A= 4 xx 10^(-4)m^(2)` `M= mu_(0)n_(1) (n_(2)l)A` `=4pi xx 10^(-7) xx 5000 xx 200 xx 4 xx 10^(-4)H` `=5.03 xx 10^(-4)H` |
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