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A solenoidal coil has 50 turns per centimetre along its length and a cross-sectional area of 4 xx 10^(-4)m^2 . 200 turns of another wire is wound round the first solenoid co-axially. The two coils are electrically insulated from each other. Calculate the mutual inductance between the two coils. |
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Answer» Solution :` n_1` = 50 turns per cm = 5000 turns per METRE `n_2l = 200,A = 4 xx 10^(-4) m^2` `M = mu_0 n_1 (n_2l) A` ` = 4pi xx 10^(-7) xx 5000 xx 200 xx 4 xx 10^(-4) H` ` = 5.03 xx 10^(-4) H` |
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