A solenoidal coil has 50 turns per centimetre along its length and a cross-sectional area of 4xx10^(-4)m^(2). 200 turns of another wire is wound round the first solenoid co-axially. The two coils are electrically insulated from each other. Calculate the mutual inductance between the two coils.

A solenoidal coil has 50 turns per centimetre along its length and a c

1.	A solenoidal coil has 50 turns per centimetre along its length and a cross-sectional area of 4xx10^(-4)m^(2). 200 turns of another wire is wound round the first solenoid co-axially. The two coils are electrically insulated from each other. Calculate the mutual inductance between the two coils.
Answer» Solution :`n_(1) = 50` turns per cm = 5000 turns per METRE `n_(2)l=200, A=4xx10^(-4)m^(2)` `M=mu_(0)n_(1)(n_(2)l)A` `=4 pi xx 10^(-7) xx 5000 xx 200 xx 4 xx 10^(-4) H` `=5.03 xx 10^(-4)H`

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A solenoidal coil has 50 turns per centimetre along its length and a cross-sectional area of 4xx10^(-4)m^(2). 200 turns of another wire is wound round the first solenoid co-axially. The two coils are electrically insulated from each other. Calculate the mutual inductance between the two coils.

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