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A solid AB has NaCl structure. If the radius of cation A^(+) is 160 pm, calculate the maximum possible value of radius of the anion B^(-)? |
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Answer» Solution :The RADIUS ratio of `A^(+)` and `B^(-)` having `Na^(+)Cl^(-)` structure is = 0.414 to 0.732 `:. ("Radius of cation, "A^(+))/("Radius of anion, "B^(-))` = 0.414 to 0.732 `:. "Radius of anion "B^(-)=("Radius of cation, "A^(+))/("0.414 to 0.732") = (160)/("0.414 to 0.732")` = 386.47 to 218.58 PM `:.` Maximum POSSIBLE value of the radius of the anion `B^(-) = 386.47` pm |
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